Eleven members of the team gave each other "high fives". If each player gave each teammate a high five, how many high fives would be given altogether?
11 * 10 = ?
either 66 or 121
The first person does 10
The second person does not have to repeat the first, so does 9
the third 8 and so on.
10+9+8+....+1
the average is 5.5, done 10 times, 55
lets check:
10+9+8+7+6+5+4_3+2+1
19+15+11+7+3
34+21
55
Bob is right. I goofed.
To find the total number of high fives, we can use the formula for combinations.
First, we need to determine the total number of pairings that can be made among the 11 members. In this case, we have 11 members, and we want to choose 2 members at a time to form a pairing. So, we use the combination formula:
C(n, r) = n! / (r! * (n-r)!)
where n is the total number of items and r is the number of items chosen at a time.
In this case, n = 11 and r = 2:
C(11, 2) = 11! / (2! * (11-2)!) = 11! / (2! * 9!) = (11 * 10) / (2 * 1) = 55
So, there are 55 total pairings possible among the 11 team members. Since each pairing involves a high five between two members, the total number of high fives given altogether would be 55.