According to Beautiful Bride magazine, the average age of a groom is now 26.2 years. A sample of 16 prospective grooms in Chicago revealed that their average age was 26.6 years with a standard deviation of 5.3 years. What is the test value for a t test of the claim?
What level of significance are you using? P = .05? P = .01? Something else?
sdmmsad
To find the test value for a t-test, we can use the formula:
t = (sample mean - population mean) / (standard deviation / sqrt(sample size))
Given:
Population mean = 26.2
Sample mean = 26.6
Standard deviation = 5.3
Sample size = 16
Substituting the given values into the formula:
t = (26.6 - 26.2) / (5.3 / sqrt(16))
Simplifying the equation:
t = 0.4 / (5.3 / 4)
t = 0.4 / 1.325
t ≈ 0.301
Therefore, the test value for the t-test of the claim is approximately 0.301.
To find the test value for a t-test, we need to compare the sample mean to the claimed population mean. In this case, the claimed population mean is 26.2 years.
The formula to calculate the t-test value is:
t = (sample mean - claimed population mean) / (standard deviation / sqrt(sample size))
Let's plug in the given information:
Sample mean (x̄) = 26.6 years
Claimed population mean (μ0) = 26.2 years
Standard deviation (σ) = 5.3 years
Sample size (n) = 16
t = (26.6 - 26.2) / (5.3 / sqrt(16))
= 0.4 / (5.3 / 4)
= 0.4 / 1.325
= 0.302
Therefore, the test value for a t-test of the claim is approximately 0.302.