What is the shortest possible length of a triangle side facing an angle of 20 degrees, if one of the other sides is 5? (answer should be a decimal number, correct within 0.001)

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  1. The shortest possible length of triangle ABC, where ∠B = 20°, and BC=5 can be obtained by making AC perpendicular to AB.
    This way, ∠A is 90° and the side AC can be obtained by the trigonometric formula:
    AC = BC*sin(20°).

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