Physics - Please Help

A 60 year old person has a threshold of hearing of 81.0 dB for a sound with frequency f=10,000 Hz. By what factor must the intensity of a sound wave of that frequency, audible to a typical young adult, (sound level=43.0 dB) be increased so that it is heard by the older person.

Thanks for any and all help!

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asked by Emily
  1. Hmmm. 81 - 43 is 38 db.

    intentity = antilog (db level/10)
    = antilog 3.8= 10^3.8

    that is almost 7000 times.

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    posted by bobpursley
  2. Thank You so much Bob Pursley!!

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    posted by Emily

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