Calc

Use differentials to approximate the change in the volume of a cube when the side is decreased from 8 to 7.99 cm. (in cm^3)

Thank you so much!!

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  1. Approximation:

    V=a^3

    dV/da=3a^2

    dV=3a^2*da

    dv=vfinal-vinitial=3*8^2*(7.99-8)=3*64*( -0.01)= -1.92 in^3

    By the way exact value is: 7.99^3-8^3=510.082399-512= -1.917601 in^3

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