a cetrifical force of 98N is acted upon a 5kg. ciculating object. If the object is moving at a radius of 1.2m ,what speed is needed to keep it in the cicular motion?

Well, let me juggle some numbers for you. When it comes to circular motion, the centripetal force is given by the formula F = mv^2/r, where F is the force, m is the mass, v is the velocity, and r is the radius. In this case, we're given that F = 98N, m = 5kg, and r = 1.2m. We want to find v.

Let's rearrange the formula to solve for v: v^2 = Fr/m. Plugging in the values, we have v^2 = (98N)(1.2m)/(5kg). To find the velocity, let me crunch those numbers.

*vigorously crunches numbers*

*vibrates with anticipation*

*dramatic pause*

The speed required to keep the object in circular motion is approximately **7.63 m/s**. So, if you want to keep things spinning smoothly, you'll need to give that object some speed!

To determine the speed needed to keep the object in circular motion, we can use the formula for centripetal force:

F = m * v^2 / r

where:
F = centripetal force (98 N)
m = mass of the object (5 kg)
v = velocity or speed of the object (unknown)
r = radius (1.2 m)

Rearranging the formula to solve for v:

v^2 = (F * r) / m

Substituting the given values:

v^2 = (98 N * 1.2 m) / 5 kg

v^2 ≈ 23.52 m^2/s^2

To determine v, we need to find the square root of both sides:

v ≈ √(23.52 m^2/s^2)

v ≈ 4.85 m/s

Hence, the speed needed to keep the object in circular motion is approximately 4.85 m/s.

To find the speed needed to keep an object in circular motion, we can use the formula for centripetal force:

F = (m * v^2) / r

where:
F is the centripetal force (given as 98 N),
m is the mass of the object (given as 5 kg),
v is the velocity of the object, and
r is the radius of the circular path (given as 1.2 m).

We can rearrange the formula to solve for velocity:

v^2 = (F * r) / m

Now, let's substitute the given values into the equation:

v^2 = (98 N * 1.2 m) / 5 kg

v^2 = 23.52 N⋅m / 5 kg

v^2 = 4.704 N⋅m/kg

To find v, we need to take the square root of both sides of the equation:

v = √(4.704 N⋅m/kg)

v ≈ 2.17 m/s

Therefore, the speed needed to keep the object in circular motion is approximately 2.17 m/s.