What is the mass of a lead sinker witha volume of 3cm3? please show work
Thank you
To find the mass of the lead sinker, we can use the formula:
Density = Mass / Volume
The density of lead is approximately 11.34 grams per cubic centimeter (g/cm^3).
Given:
Volume = 3 cm^3
Density of lead = 11.34 g/cm^3
Substituting these values into the formula, we can solve for the mass:
Density = Mass / Volume
11.34 g/cm^3 = Mass / 3 cm^3
To solve for the mass, we can rearrange the equation as follows:
Mass = Density * Volume
Mass = 11.34 g/cm^3 * 3 cm^3
Calculating the mass:
Mass = 34.02 g
Therefore, the mass of the lead sinker with a volume of 3 cm^3 is 34.02 grams.
To find the mass of a lead sinker, we need to know its density. The density of a substance is defined as mass per unit volume. In this case, we are given the volume of the lead sinker as 3 cm³.
The formula for density (ρ) is:
ρ = mass (m) / volume (V)
To find the mass (m), we rearrange the formula:
m = ρ * V
Therefore, we need to know the density of lead. The density of lead is approximately 11.34 grams per cubic centimeter (g/cm³).
Now, we can substitute the values into the formula:
m = 11.34 g/cm³ * 3 cm³
Multiplying the density (11.34 g/cm³) by the volume (3 cm³), we get:
m = 34.02 g
So, the mass of the lead sinker with a volume of 3 cm³ is 34.02 grams.
Mass is density times volume.
I recommend that you look up the density of lead and do the work yourself.
The volume should be written as 3 cm^3.