Given that 12g of carbon combines completely with 16g of oxygen to form carbon monoxide, how many grams of carbon monoxide can be made from 48g of carbon and 48g of oxygen
with 48 g Oxygen, you need 36 grams of C. Total CO is 48+36. yes, you have excess C
I am really wondering why your teacher is giving you this in physics. Is your physics teacher teaching chem?
This is a basic phyisics class.
Thank you so much!!!!1
To find out how many grams of carbon monoxide can be made from 48g of carbon and 48g of oxygen, we need to determine the limiting reactant. The limiting reactant is the reactant that is completely consumed and limits the amount of product that can be formed.
1. Start by calculating the number of moles for each reactant:
- Moles of carbon = mass of carbon / molar mass of carbon (12g/mol)
Moles of carbon = 48g / 12g/mol = 4 moles of carbon
- Moles of oxygen = mass of oxygen / molar mass of oxygen (16g/mol)
Moles of oxygen = 48g / 16g/mol = 3 moles of oxygen
2. Next, determine the mole ratio between carbon monoxide and the reactants using the balanced chemical equation:
The balanced chemical equation for the reaction is:
2 C + O2 -> 2 CO
From this equation, we can see that 2 moles of carbon react with 1 mole of oxygen to produce 2 moles of carbon monoxide.
3. Now, compare the moles of carbon and oxygen to determine the limiting reactant:
The mole ratio of carbon to oxygen is 2:1. Since we have 4 moles of carbon and 3 moles of oxygen, we can see that oxygen is the limiting reactant because it is in a lower quantity.
4. Calculate the maximum number of moles of carbon monoxide formed by using the mole ratio:
The mole ratio of carbon monoxide to oxygen is 2:1. Since oxygen is the limiting reactant, we'll use its moles for calculation.
Moles of carbon monoxide = Moles of oxygen x (2 moles of CO / 1 mole of O2)
Moles of carbon monoxide = 3 moles x (2 moles of CO / 1 mole of O2) = 6 moles of carbon monoxide
5. Finally, determine the mass of carbon monoxide formed using the number of moles and molar mass:
Mass of carbon monoxide = Moles of carbon monoxide x molar mass of carbon monoxide
Molar mass of carbon monoxide = molar mass of carbon (12g/mol) + molar mass of oxygen (16g/mol)
Molar mass of carbon monoxide = 12g/mol + 16g/mol = 28g/mol
Mass of carbon monoxide = 6 moles x 28g/mol = 168g
Therefore, 168 grams of carbon monoxide can be made from 48 grams of carbon and 48 grams of oxygen.