The Ksp of calcium carbonate is 4.5E-9. What si the concentration of calcium carbonate in equilibirum in water?

-do i make an ICE table and please explain Ksp.

Yes, you make an ICE table. Ksp stands for solubility product constant. Ksp is calculated by multiplying the concentrations of the ions by each other AFTER raising each concn to the power indicated by the coefficient in the balanced ionization equation.

CaCO3(s) ==> Ca^2+ + CO3^2-
let x stand for solubility CaCO3 in moles/L. Then
................CaCO3 ==> Ca^2+ CO3^2-
initial...................0.....0
change.....................x.....x
equil......................x.....x
Substitute into Ksp expression and solve for x. The answer is in M.
Ksp = 4.5E-9 = (Ca^2+)(CO3^2-)

To determine the concentration of calcium carbonate in equilibrium in water, you can start by setting up an ICE (Initial, Change, Equilibrium) table. Here's how you can do it:

1. Write the balanced chemical equation for the dissolution of calcium carbonate in water:
CaCO3(s) ⇌ Ca2+(aq) + CO32-(aq)

2. Set up the ICE table with the initial concentration of calcium carbonate (CaCO3(s)) as zero and the change in concentration of the product ions (Ca2+(aq) and CO32-(aq)) as "x".

| CaCO3(s) | Ca2+(aq) | CO32-(aq) |
-------------------------------------------------
I | 0 | 0 | 0 |
C | -x | x | x |
E | -x | x | x |

3. Since the stoichiometry of the balanced equation is 1:1:1, the concentration of calcium carbonate (CaCO3) in equilibrium will be equal to "x".

4. The solubility product constant (Ksp) relates to the equilibrium concentrations of the product ions. In this case, the Ksp of calcium carbonate is given as 4.5E-9. The Ksp expression for the dissolution reaction is:

Ksp = [Ca2+][CO32-]

5. Substitute the equilibrium concentrations into the Ksp expression:
4.5E-9 = x * x

6. Solve the equation for x by taking the square root of both sides:
√(4.5E-9) = x

7. Calculate the concentration of calcium carbonate in equilibrium in water:
x = 6.71E-5 M

Therefore, the concentration of calcium carbonate in equilibrium in water is 6.71E-5 M.