If tums is added to 20.0 mL of 0.400 M HCl solution, how many grams of CO2 gas are produced?
How many grams Tums do you have? What is the percent CaCO3/Mg(OH)2/ whatever. If HCl is the limiting reagent there will be moles HCl = M x L = 0.008
moles CaCO3 = 1/2 x 0.008 = 0.004
L CO2 at STP = moles x 22.4 L/mol = ??
To determine the number of grams of CO2 gas produced when Tums is added to an HCl solution, we first need to write the balanced chemical equation for the reaction.
The active ingredient in Tums is calcium carbonate (CaCO3). When CaCO3 reacts with HCl, it forms calcium chloride (CaCl2), water (H2O), and carbon dioxide (CO2).
The balanced chemical equation for this reaction is:
CaCO3 (s) + 2 HCl (aq) -> CaCl2 (aq) + H2O (l) + CO2 (g)
From the equation, we can see that 1 mole of CaCO3 reacts with 2 moles of HCl to produce 1 mole of CO2.
To determine the number of moles of HCl in the solution, we can use the equation:
Moles = Concentration (M) x Volume (L)
Given:
Concentration of HCl = 0.400 M
Volume of HCl solution = 20.0 mL = 0.020 L
Moles of HCl = 0.400 M x 0.020 L = 0.008 moles
Since the stoichiometric ratio between HCl and CO2 is 2:1, we can determine the number of moles of CO2 produced by dividing the moles of HCl by 2:
0.008 moles HCl / 2 = 0.004 moles CO2
Now, to determine the mass of CO2 produced, we need to multiply the number of moles by the molar mass of CO2. The molar mass of CO2 is calculated as follows:
Molar mass of C = 12.01 g/mol
Molar mass of O = 16.00 g/mol (x2 since there are two oxygen atoms)
Molar mass of CO2 = 12.01 g/mol + 16.00 g/mol x 2 = 44.01 g/mol
Mass of CO2 = 0.004 moles CO2 x 44.01 g/mol = 0.176 g
Therefore, when Tums is added to 20.0 mL of a 0.400 M HCl solution, 0.176 grams of CO2 gas are produced.
To determine the number of grams of CO2 gas produced when Tums is added to the HCl solution, we need to know the balanced chemical equation for the reaction between Tums and HCl.
The chemical equation for the reaction between Tums (calcium carbonate, CaCO3) and HCl (hydrochloric acid) is:
CaCO3 + 2 HCl → CaCl2 + CO2 + H2O
From this equation, we can see that 1 mole of CaCO3 produces 1 mole of CO2. Now, we need to determine the number of moles of CaCO3.
First, let's calculate the number of moles of HCl in the solution. We are given that the volume of the HCl solution is 20.0 mL and the concentration is 0.400 M.
The number of moles of HCl can be calculated using the formula:
moles = concentration × volume
moles = 0.400 M × 0.0200 L (converting mL to L)
moles = 0.00800 moles
Since the balanced chemical equation shows that 1 mole of CaCO3 reacts with 2 moles of HCl to produce 1 mole of CO2, we can say that the number of moles of CaCO3 is half the number of moles of HCl:
moles of CaCO3 = 0.00800 moles / 2
moles of CaCO3 = 0.00400 moles
Finally, to determine the mass of CO2 produced, we need to know the molar mass of CO2, which is 44.01 g/mol.
mass of CO2 = moles of CaCO3 × molar mass of CO2
mass of CO2 = 0.00400 moles × 44.01 g/mol
mass of CO2 = 0.176 g
Therefore, when Tums is added to 20.0 mL of 0.400 M HCl solution, approximately 0.176 grams of CO2 gas are produced.