HOW DO I FIGURE OUT -X2-5X-9=0
Are you 'solving' for x in x^2 - 5x - 9 = 0
If so, then x=(5 ± √(25-4(1)(-9))/2
= (5 ± √61)/2 by using the quadratic formula
i am also stumped by this question and the equation is x squared. is x^2 still the same answer. Thanks
To figure out the value of x that satisfies the equation -x^2 - 5x - 9 = 0, you can use the quadratic formula. The quadratic formula states that for a quadratic equation in the form ax^2 + bx + c = 0, the value of x can be found using the formula:
x = (-b ± √(b^2 - 4ac)) / 2a
In the given equation, a = -1, b = -5, and c = -9. Plugging these values into the quadratic formula, we can find the solutions.
First, let's calculate the discriminant, which is the expression under the square root: b^2 - 4ac.
Discriminant = (-5)^2 - 4(-1)(-9)
= 25 - 36
= -11
Since the discriminant is negative (-11 < 0), there are no real solutions to the equation. In other words, this equation does not have any real values of x that satisfy it. The graph of this equation will open downwards and not intersect the x-axis.
So, the answer is that there are no real solutions for the equation -x^2 - 5x - 9 = 0.