a bag of marbles can be divided in equal shares among 2,3,4,5, or 6 friends. What is the least number of marbles that the bag could contain?
2
3
2*2
5
2*3
has to have 4*3*5 = 60
It’s obviously 60
*whoosh*
Lol
48
fartz
To find the least number of marbles that the bag could contain, we need to find the least common multiple (LCM) of 2, 3, 4, 5, and 6.
The LCM is the smallest number that is a multiple of all the given numbers. We can use prime factorization to find the LCM.
Prime factorization of the given numbers:
2 = 2
3 = 3
4 = 2 * 2
5 = 5
6 = 2 * 3
To find the LCM, we take the highest power of each prime factor that appears in the prime factorization of any of the given numbers. In this case, the LCM would be 2 * 2 * 3 * 5 = 60.
So, the bag of marbles could contain at least 60 marbles.
for me its 2 im not sure but my answer is 2
Let's look at the multiples of 6
6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78
Now, which of the above numbers are divisible by 5?
Which of the numbers divisible by 5 are also divisible by 2, 3, and 4?