maths

We can cut a square diagonally in half to get two triangles. Suppose the
perimeter of the square is 3cm longer than the perimeter of a resulting triangle.
What is the perimeter of the square?

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  1. Let a-the side of the square, then
    sqrt(a^2+a^2)=a*sqrt(2)-diagonal.
    On the condition of the problem
    4a=2a+a*sqrt(2)+3
    a(2-sqrt(2))=3
    a=3/(2-sqrt(2))=3(2+sqrt(2))/2
    The perimeter of the square=4a=6(2+sqrt(2))=20.49cm

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