In a jar there are 18 marbles. There are 3 red marbles, 9 green marbles, 6 blue marbles. What is the probability of drawing (with replacement) a red marble and then a green marble? Please write the answer in fraction form? Show how you did all the work.
dont you just add all of it and then you put that number on the bottom and then you have the red and green and then you put it on top of the fraction and then multiply and simplify
Probability that all events occur is found by multiplying the individual probabilities.
3/18 * 9/16 = ?
To find the probability of drawing a red marble and then a green marble, we need to first find the probabilities of each event separately and then multiply them together.
1. Probability of drawing a red marble:
There are 18 marbles in total, and 3 of them are red. So, the probability of drawing a red marble is 3/18.
2. Probability of drawing a green marble:
After the first marble is drawn and replaced, there are still 18 marbles in the jar, and 9 of them are green. So, the probability of drawing a green marble is also 9/18.
To find the probability of both events happening, we multiply the probabilities together:
Probability of drawing a red marble and then a green marble = (3/18) * (9/18)
To simplify this fraction, we can divide both the numerator and denominator by their greatest common divisor, which is 3:
Probability of drawing a red marble and then a green marble = (1/6) * (3/6)
Simplifying further, we multiply the numerators together and the denominators together:
Probability of drawing a red marble and then a green marble = (1 * 3) / (6 * 6)
And the final answer is:
Probability of drawing a red marble and then a green marble = 3/36
Therefore, the probability of drawing a red marble and then a green marble is 3/36.