A solution has a volume of 2L and contains 36g of glucose, what is the molaritiy of the solution?
molarity= massinGrams/molmass / 2= 18/molmassGlucose
To find the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters).
First, we need to determine the number of moles of glucose in the solution. We can use the formula:
moles = mass / molar mass
The molar mass of glucose (C6H12O6) is approximately 180.16 g/mol.
moles = 36 g / 180.16 g/mol
moles = 0.2 mol
Next, we can calculate the molarity using the formula:
molarity (M) = moles / volume (in liters)
Given that the volume of the solution is 2 L:
molarity = 0.2 mol / 2 L
molarity = 0.1 M
Therefore, the molarity of the solution is 0.1 M.
To find the molarity of a solution, you need to know the number of moles of solute (in this case, glucose) and the volume of the solution.
First, you need to calculate the number of moles of glucose using its molecular weight. Glucose has a molecular weight of 180.16 g/mol. By dividing the mass of glucose (36g) by its molecular weight, you can find the number of moles:
Number of moles = mass / molecular weight
= 36g / 180.16 g/mol
= 0.2 mol
Next, divide the number of moles of glucose by the volume of the solution in liters to find the molarity:
Molarity (M) = number of moles / volume (in liters)
= 0.2 mol / 2L
= 0.1 M
Therefore, the molarity of the solution is 0.1 M.