which is the correct formula for the combustion of S8 at STP, (a) or (b)?
a) S8(s) + 4O2(g) ==> 4SO2(g)
b) S8(s) + 8O2(g) ==> 8SO2(g)
someone told me it is (a), but that is not balanced... or is it right?
please and thank you!!!!
To determine which formula is correct for the combustion of S8 at STP, we need to balance the chemical equation by ensuring that the number of atoms on both sides of the equation is equal.
Let's start by examining option (a):
a) S8(s) + 4O2(g) ==> 4SO2(g)
In this equation, there are 8 sulfur (S) atoms on the left side but only 4 sulfur atoms on the right side. This means the equation is unbalanced.
Now, let's examine option (b):
b) S8(s) + 8O2(g) ==> 8SO2(g)
In this equation, there are 8 sulfur (S) atoms on the left side and 8 sulfur atoms on the right side, which means the equation is balanced.
Therefore, the correct formula for the combustion of S8 at STP is:
b) S8(s) + 8O2(g) ==> 8SO2(g)
Option (a) is not balanced, so it is not the correct formula.