A gas occupies 30L at 25 celsius. What volume will it occupy at 200 celsius at the same pressure?
P2V2/T2=P1V1/T1
change temps to Kelvins
V2=30L*T2/T1
Thank you
To solve this question, you can use the combined gas law formula, which relates the initial and final volumes, temperatures, and pressures of a gas.
The combined gas law formula is:
(P1 * V1) / (T1) = (P2 * V2) / (T2)
Where:
P1 and P2 are the initial and final pressures of the gas
V1 and V2 are the initial and final volumes of the gas
T1 and T2 are the initial and final temperatures of the gas
In this case, we are given:
V1 = 30L (initial volume)
T1 = 25°C (initial temperature)
Let's assume that the pressure remains constant.
We need to find V2, the final volume, when T2 is 200°C.
Since we know that P1 = P2 (constant pressure), we can modify the formula as:
(V1) / (T1) = (V2) / (T2)
Now, we can plug in the values we know:
(30L) / (25 + 273.15) = (V2) / (200 + 273.15)
Note: We convert the temperatures to Kelvin by adding 273.15 to the Celsius temperatures.
Simplifying the equation:
30L / 298.15K = V2 / 473.15K
To find V2, we can rearrange the equation:
V2 = (30L * 473.15K) / 298.15K
V2 ≈ 47.62L
Therefore, the gas would occupy approximately 47.62 liters at 200°C at the same pressure.