How do you find the pH for 0.010M of HNO3?
It's 2.0
pH = -log(H^+) and since HNO3 is a strong acid, (H^+) = (HNO3), so
pH = -log(0.01) = -(2.0) = +2.0
pH = -log(H^+) and since HNO3 is a strong acid, (H^+) = (HNO3), so
pH = -log(0.01) = -(2.0) = +2.0