math

Please help me solve the following. Thanks,

Write m^p = q using logarithms.

Solve (1/e)^2x = 14

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  1. by definition m^p = q is the same as

    logm q = p

    for your second question

    (1/e)^2x = 14

    e^(-2x) = 14
    -2x = ln 14
    x = -1/2 ln 14

    Are you not familiar with the basic properties of logs and exponents?
    These type of questions require you to know those.

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