what is the balance equation of CH3COOH(aq)+NH3(aq)
CH3COOH(aq) + NH3(aq) ==> CH3COONH4(aq).
We could do this step wise and obtain this.
CH3COOH ==> CH3COO- + H+ (ionization)
NH3 + HOH ==> NH4+ + OH- (ionization)
CH3COO- + NH4+ ==> CH3COONH4 and
H+ + OH- ==> H2O (reaction of ions)
To determine the balanced equation for the reaction between acetic acid (CH3COOH) and ammonia (NH3), we need to identify the products formed.
Acetic acid (CH3COOH) is a weak acid, and ammonia (NH3) is a weak base. When they react, they undergo a neutralization reaction to form a salt, in this case, ammonium acetate (NH4CH3COO). The reaction can be represented as follows:
CH3COOH(aq) + NH3(aq) → NH4CH3COO(aq)
To balance this equation, we need to ensure that the same number of atoms of each element appear on both sides of the equation.
First, let's start with the carbon (C) atoms. There is one carbon atom on the left side (CH3COOH) and one carbon atom on the right side (NH4CH3COO), so the carbon is already balanced.
Next, let's balance the hydrogen (H) atoms. There are four hydrogen atoms on the left side (CH3COOH) and five hydrogen atoms on the right side (NH4CH3COO), so we need to add one more hydrogen atom to the left side:
CH3COOH(aq) + NH3(aq) → NH4CH3COO(aq) + H2O(l)
Finally, let's balance the oxygen (O) atoms. There are two oxygen atoms on the left side (CH3COOH) and two oxygen atoms on the right side (NH4CH3COO), so the oxygen is already balanced.
The balanced equation for the reaction between acetic acid and ammonia is:
CH3COOH(aq) + NH3(aq) → NH4CH3COO(aq) + H2O(l)