A sample of O2 gas was collected over water at 23ºC and 711 torr. What is the partial pressure of the O2? (The vapor pressure of water at 23ºC is 21.2 torr.)

Partial pressure of O2:_____torr

To find the partial pressure of O2, we need to subtract the vapor pressure of water from the total pressure.

Partial pressure of O2 = Total pressure - Vapor pressure of water

Total pressure = 711 torr
Vapor pressure of water at 23ºC = 21.2 torr

Partial pressure of O2 = 711 torr - 21.2 torr

Partial pressure of O2 = 689.8 torr

Therefore, the partial pressure of O2 is 689.8 torr.

To find the partial pressure of the O2 gas, we need to subtract the vapor pressure of water from the total pressure.

The vapor pressure of water at 23ºC is given as 21.2 torr.

Given that the total pressure is 711 torr, we can calculate the partial pressure of the O2 gas as follows:

Partial pressure of O2 = Total pressure - Vapor pressure of water

Partial pressure of O2 = 711 torr - 21.2 torr

Partial pressure of O2 = 689.8 torr

Therefore, the partial pressure of the O2 gas is 689.8 torr.

I answered this below.

Remember Dalton's Law.
Ptotal = PO2 + PH2O

7322