A sample of O2 gas was collected over water at 23ºC and 711 torr. What is the partial pressure of the O2? (The vapor pressure of water at 23ºC is 21.2 torr.)
Partial pressure of O2:_____torr
To find the partial pressure of O2, we need to subtract the vapor pressure of water from the total pressure.
Partial pressure of O2 = Total pressure - Vapor pressure of water
Total pressure = 711 torr
Vapor pressure of water at 23ºC = 21.2 torr
Partial pressure of O2 = 711 torr - 21.2 torr
Partial pressure of O2 = 689.8 torr
Therefore, the partial pressure of O2 is 689.8 torr.
To find the partial pressure of the O2 gas, we need to subtract the vapor pressure of water from the total pressure.
The vapor pressure of water at 23ºC is given as 21.2 torr.
Given that the total pressure is 711 torr, we can calculate the partial pressure of the O2 gas as follows:
Partial pressure of O2 = Total pressure - Vapor pressure of water
Partial pressure of O2 = 711 torr - 21.2 torr
Partial pressure of O2 = 689.8 torr
Therefore, the partial pressure of the O2 gas is 689.8 torr.
I answered this below.
Remember Dalton's Law.
Ptotal = PO2 + PH2O