i don't know how to solve this. looked through all my notes but i'm not sure what kind of formula i am to use or if i even need one! please help me to understand the theory behind this:

"calculate the work need to make room for the products in the combustion of S8(s) to SO2(g) at 1 atm and 0 degree C."

thank you for your time!

* chem- repost - bobpursley, Sunday, April 17, 2011 at 7:29pm

work at constant temp and pressure, will be pressure*deltaV

in this case, you get two volumes of product

S8(s)+4O2>>8SO2

work= p*dV on a per S8 mole basis,

work= 101.3kPa*4*22.4dm^3*1m^3/1000dm^3

work= above in Joules

check my thinking

* chem- repost - please, help me , Sunday, April 17, 2011 at 8:06pm

thank you for responding, where did you get "4 x 22.4dm^3/1000dm^3" from though? I'm not sure where to get volume from

on a per mole basis, you release 4 moles of new gas. At STP, it occupies 2*22.4 liters

oh i didn't know that before, thank you very much! :)

To understand the theory behind calculating the work needed to make room for the products in the combustion of S8(s) to SO2(g), let's break it down step by step:

1. Determine the chemical equation: The given equation is S8(s) + 4O2(g) -> 8SO2(g). This means that for every 1 mole of S8 reacted, we get 8 moles of SO2.

2. Find the change in volume: The change in volume can be determined by looking at the difference in the number of moles of gas on the reactant and product side of the equation. In this case, there are no gas moles on the reactant side, but on the product side, there are 8 moles of SO2 produced. So, the change in volume is equal to the volume of 8 moles of SO2.

3. Convert volume to a standard unit: The volume needs to be converted to a standard unit, such as liters or cubic meters. In the provided solution, the volume is given in dm^3, but it needs to be converted to m^3. This is done by dividing the volume by 1000 since there are 1000 dm^3 in 1 m^3.

4. Calculate the work: The formula for work at constant temperature and pressure is W = P * ΔV, where W is the work, P is the pressure, and ΔV is the change in volume. In this case, the pressure is given as 1 atm.

Now let's put it all together using the values provided in the solution:

Pressure (P) = 1 atm
Change in volume (ΔV) = 8 moles of SO2 * volume of 1 mole of SO2 (which is 22.4 dm^3) / 1000 dm^3 to convert to m^3 = 8 * 22.4 / 1000 = 0.1792 m^3

Work (W) = Pressure * Change in volume = 1 atm * 0.1792 m^3 = 0.1792 atm * m^3

To convert atm * m^3 to Joules, you can use the conversion factor 1 atm * m^3 = 101.3 Joules.

Therefore, the work required to make room for the products in the combustion of S8(s) to SO2(g) is 0.1792 atm * m^3 * (101.3 J / 1 atm * m^3) = 18.14 Joules.

Hope this explanation helps! Let me know if you have any further questions.