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If 237 mL of O2, measured at STP, are obtained by the decomposition of the KClO3 in a 5.44 g mixture of KCl and KClO3,
2KClO3(s)-->2KCl(s)+3O2(g)
what is the percent by mass of KClO3 in the mixture?

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Sam

  1. %KClO3 = (mass KClO3/mass sample) x 100 = ??
    mass KClO3 = what?
    0.237 g O2 x (1 mole O2/22.4L O2) x (2 moles KClO3/3 moles O2) x (122.6 g KClO3/mole KClO) = grams KClO3.

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    DrBob222

  2. mass percent of oxygen in potassium chlorate:

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    Anonymous

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