A man of mass 80 kg and density 970 kg/m3 stands in a shallow pool with 31% of the volume of his body below water. Calculate the normal force the bottom of the pool exerts on his feet. (Take the positive direction to be up. Indicate the direction with the sign of your answer.)

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1. density of water = 1000

volume of man = 80 kg / 970kg/m^3 = .0825m^3

.31*.0825 = .0256 m^3

buoyant force up on man = .0256*1000*9.81 = 251 Newtons

weight of man = 80*9.81 = 785 Newtons

weight - buoyancy = 785 -251 = 534 N

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