The length of a rectangle is fixed at 11cm. What widths will make the perimeter greater than 72cm?

P = 2L + 2W

72< 22 + 2W

50 >2W

50 < 2w (correction)

Thanks, Matt.

To find the widths that will make the perimeter greater than 72 cm, we need to consider the perimeter formula for a rectangle:

Perimeter = 2 * (length + width)

We are given that the length is fixed at 11 cm, so the formula becomes:

Perimeter = 2 * (11 + width)

Now, we can set up an inequality to find the widths that make the perimeter greater than 72 cm:

2 * (11 + width) > 72

First, let's simplify the inequality:

22 + 2 * width > 72

Next, let's isolate the width by subtracting 22 from both sides:

2 * width > 72 - 22

2 * width > 50

Finally, let's solve for the width:

width > 50 / 2

width > 25

Therefore, any width greater than 25 cm will make the perimeter of the rectangle greater than 72 cm.