The length of a rectangle is fixed at 11cm. What widths will make the perimeter greater than 72cm?
P = 2L + 2W
72< 22 + 2W
50 >2W
50 < 2w (correction)
Thanks, Matt.
To find the widths that will make the perimeter greater than 72 cm, we need to consider the perimeter formula for a rectangle:
Perimeter = 2 * (length + width)
We are given that the length is fixed at 11 cm, so the formula becomes:
Perimeter = 2 * (11 + width)
Now, we can set up an inequality to find the widths that make the perimeter greater than 72 cm:
2 * (11 + width) > 72
First, let's simplify the inequality:
22 + 2 * width > 72
Next, let's isolate the width by subtracting 22 from both sides:
2 * width > 72 - 22
2 * width > 50
Finally, let's solve for the width:
width > 50 / 2
width > 25
Therefore, any width greater than 25 cm will make the perimeter of the rectangle greater than 72 cm.