calculate the number of oxygen needed to oxidize 12.5grams of glucose (C6H12O6) into carbon dioxide and water. (Combustion reaction)
*i'll just repost my answer~ :)
first we write the combustion reaction:
C6H12O6 + O2 -> H2O + CO2
then we balance it:
C6H12O6 + 6O2 -> 6H2O + 6CO2
since mass of glucose is given, we get its molecular weight,, from the periodic table mass of each element in glucose is
H = 1 , C = 12 , O = 16
6*12 + 12*1 + 6*16 = 180 g/mol
thus,
12.5 g C6H12O6 * (1 mol C6H12O6 / 180 g C6H12O6) * (6 mol O2 / 1 mol C6H12O6) = 0.4167 mol O2
or in grams, (O2 = 32 g/mol)
32*0.4167 = 13.33 g O2
hope this helps~ :)
To calculate the number of oxygen molecules needed to oxidize 12.5 grams of glucose (C6H12O6), we need to balance the combustion reaction equation for glucose.
The balanced equation for the combustion of glucose is:
C6H12O6 + 6O2 -> 6CO2 + 6H2O
From the balanced equation, we can see that 1 mole of glucose reacts with 6 moles of oxygen to produce 6 moles of carbon dioxide and 6 moles of water.
Let's calculate the molar mass of glucose (C6H12O6):
C: 6 x 12.01 g/mol = 72.06 g/mol
H: 12 x 1.01 g/mol = 12.12 g/mol
O: 6 x 16.00 g/mol = 96.00 g/mol
Total molar mass of glucose (C6H12O6) = 72.06 g/mol + 12.12 g/mol + 96.00 g/mol = 180.18 g/mol
Now, we can calculate the number of moles of glucose by dividing the given mass by the molar mass:
Number of moles of glucose = 12.5 g / 180.18 g/mol ≈ 0.069 moles
According to the balanced equation, we need 6 moles of oxygen for every mole of glucose.
Number of moles of oxygen = 0.069 moles × 6 = 0.414 moles
Finally, we can convert the number of moles of oxygen to the number of oxygen molecules using Avogadro's number, which is approximately 6.022 × 10^23 molecules/mol:
Number of oxygen molecules = 0.414 moles × 6.022 × 10^23 molecules/mol ≈ 2.49 × 10^23 molecules
Therefore, approximately 2.49 × 10^23 oxygen molecules are needed to oxidize 12.5 grams of glucose into carbon dioxide and water.
To calculate the number of oxygen atoms needed to oxidize glucose (C6H12O6) into carbon dioxide (CO2) and water (H2O) through a combustion reaction, we need to follow a few steps:
Step 1: Write and balance the chemical equation for the combustion of glucose.
C6H12O6 + O2 → CO2 + H2O
Step 2: Calculate the molar mass of glucose.
The molar mass of glucose (C6H12O6) can be calculated by summing the molar masses of each element present in its formula.
C: 6 atoms × atomic mass of C = 6 × 12.01 g/mol = 72.06 g/mol
H: 12 atoms × atomic mass of H = 12 × 1.01 g/mol = 12.12 g/mol
O: 6 atoms × atomic mass of O = 6 × 16.00 g/mol = 96.00 g/mol
Molar mass of glucose (C6H12O6) = 72.06 g/mol + 12.12 g/mol + 96.00 g/mol = 180.18 g/mol
Step 3: Calculate the moles of glucose.
We can use the given mass of 12.5 grams and the molar mass calculated in step 2 to determine the number of moles of glucose.
Moles of glucose = Mass of glucose / Molar mass of glucose
Moles of glucose = 12.5 g / 180.18 g/mol
Step 4: Determine the stoichiometry of the balanced equation.
From the balanced equation, we can see that 1 mole of glucose reacts with 6 moles of oxygen to produce 6 moles of carbon dioxide and 6 moles of water.
C6H12O6 + O2 → 6 CO2 + 6 H2O
Step 5: Calculate the moles of oxygen required.
Using the stoichiometry from step 4, we can determine the moles of oxygen needed.
Moles of oxygen = Moles of glucose × (6 moles of O2 / 1 mole of glucose)
Step 6: Calculate the number of oxygen atoms.
Finally, we can determine the number of oxygen atoms needed by multiplying the moles of oxygen by Avogadro's number (6.022 × 10^23 atoms/mol).
Number of oxygen atoms = Moles of oxygen × Avogadro's number
By following these steps, you can calculate the number of oxygen atoms needed to oxidize 12.5 grams of glucose into carbon dioxide and water through the combustion reaction.