What is the final volume of 945 mL of neon gas at 174°C if the gas is cooled to 58.5°C? Assume the pressure and the amount of gas are held constant.
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To find the final volume of the neon gas, we can use the combined gas law equation:
(P1 * V1) / (T1) = (P2 * V2) / T2
Where:
P1 = Initial pressure (assumed constant)
V1 = Initial volume (945 mL)
T1 = Initial temperature (174°C)
P2 = Final pressure (assumed constant)
V2 = Final volume (to be calculated)
T2 = Final temperature (58.5°C)
Since the pressure and the amount of gas are held constant, we can simplify the equation to:
V1 / T1 = V2 / T2
Now we can substitute the given values into the equation:
V1 / T1 = V2 / T2
945 mL / 174°C = V2 / 58.5°C
To solve for V2, cross-multiply and then divide:
945 mL * 58.5°C = V2 * 174°C
(945 mL * 58.5°C) / 174°C = V2
(55132.5 mL*°C) / 174°C = V2
316.8 mL = V2
Therefore, the final volume of the neon gas, when cooled to 58.5°C, is 316.8 mL.