How many moles of aluminum oxide can be produced from 12.8 moles of oxygen gas (O2) reacting with excess aluminun (Al)? useing this equation:
---- I don't get how to do these?
4Al(s) + 3O2--> 2Al2O3(s)
All of these are "simple" (meaning they are not limiting reagent problems) and are done the same way. Here is a solved example. Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To determine the number of moles of aluminum oxide produced from 12.8 moles of oxygen gas (O2), you will need to calculate the stoichiometry of the reaction. The balanced equation provides the mole ratio between oxygen gas and aluminum oxide.
From the balanced equation:
4 Al(s) + 3 O2(g) → 2 Al2O3(s)
The coefficient of O2 in the equation is 3, which means that for every 3 moles of O2, 2 moles of Al2O3 are produced.
Given that you have 12.8 moles of O2, you can set up a proportion to find the number of moles of Al2O3:
3 moles O2 / 2 moles Al2O3 = 12.8 moles O2 / x moles Al2O3
Cross-multiplying the equation:
3x = 12.8 * 2
3x = 25.6
Dividing both sides by 3, you find:
x = 8.53 moles
Therefore, 12.8 moles of O2 will produce 8.53 moles of Al2O3.
To determine how many moles of aluminum oxide can be produced from 12.8 moles of oxygen gas (O2) reacting with excess aluminum (Al), we need to use the balanced equation provided:
4Al(s) + 3O2 -> 2Al2O3(s)
In this equation, we can see that the ratio between aluminum (Al) and oxygen gas (O2) is 4:3, meaning that 4 moles of aluminum react with 3 moles of oxygen gas to produce 2 moles of aluminum oxide.
To find the number of moles of aluminum oxide produced, we can set up a proportion using the given amount of oxygen gas:
12.8 moles of oxygen gas (O2) / 3 moles of oxygen gas (O2) = x moles of aluminum oxide / 2 moles of aluminum oxide
Cross-multiplying and solving for x, we get:
x = (12.8 moles of oxygen gas / 3 moles of oxygen gas) * 2 moles of aluminum oxide
x = 8.53 moles of aluminum oxide
Therefore, from the reaction of 12.8 moles of oxygen gas with excess aluminum, approximately 8.53 moles of aluminum oxide can be produced.