Mr. Ranier's car uses about 1.6 fluid ounces of gas per minute when the engine is idling. One night, he parked his car but forgot to turn off the motor. He had just filled his tank. His tank holds 12 gallons. About how many hours will it take before his car runs out of gas?
Convert gallons to ounces (1 gallon = 128 ounces, 12 gallons = ?) and divide by 1.6. Then convert minutes to hours.
To determine how many hours it will take for Mr. Ranier's car to run out of gas, we need to calculate how much gas is consumed per hour.
First, we convert the consumption rate from fluid ounces per minute to gallons per hour. There are 128 fluid ounces in a gallon and 60 minutes in an hour. So, the car consumes 1.6 fluid ounces per minute * (1 gallon/128 fluid ounces) * (60 minutes/1 hour) = 0.075 gallons per hour when idling.
Next, we divide the total tank capacity of 12 gallons by the consumption rate of 0.075 gallons per hour to find the number of hours until the car runs out of gas:
Time in hours = Tank capacity / Consumption rate
Time in hours = 12 gallons / 0.075 gallons per hour
Time in hours = 160 hours
Therefore, it will take approximately 160 hours for Mr. Ranier's car to run out of gas if he forgets to turn off the engine.