Assuming that the volumes are additive, what volume of water must be added to 35.0mL of 23.0 M HCl to make a solution which is 3.00 M?
mL x M = mL x M
35.0 mL x 23.0M = mL x 3.00M
Solve for mL which will be the TOTAL volume. The volume to be added will be 35.0 mL less than that.
Well, it's time for some clown math! Let's get started.
To determine the volume of water we need to add, we can use the equation:
(M1)(V1) + (M2)(V2) = (M3)(V3)
M1 is the initial molarity of HCl, which is 23.0 M. V1 is the initial volume of HCl, which is 35.0 mL. M2 is the molarity of water, which is 0 M since water doesn't have a molarity or affect the concentration. V2 is the volume of water we want to find. M3 is the final molarity of the solution we want to make, which is 3.00 M. V3 is the final volume of the solution we want to find.
So, let's plug in the values:
(23.0 M)(35.0 mL) + (0 M)(V2) = (3.00 M)(V3)
Since (0 M)(V2) is equal to 0, we can simplify the equation to:
(23.0 M)(35.0 mL) = (3.00 M)(V3)
Now, let's solve for V3:
(23.0 M)(35.0 mL) / (3.00 M) = V3
Calculating this gives us:
V3 = 268.33 mL
So, you would need roughly 268.33 mL of water to add to 35.0 mL of 23.0 M HCl to make a solution with a final concentration of 3.00 M. Just make sure not to spill any water while you're at it!
To solve this problem, we need to use the formula for dilution:
C1V1 = C2V2
Where:
C1 = initial concentration
V1 = initial volume
C2 = final concentration
V2 = final volume
In this case:
C1 = 23.0 M
V1 = 35.0 mL
C2 = 3.00 M
V2 = ?
Let's rearrange the formula to solve for V2:
V2 = (C1V1) / C2
Now we can substitute the given values into the equation:
V2 = (23.0 M * 35.0 mL) / 3.00 M
Calculating this expression:
V2 = (805.0) / 3.00
V2 ≈ 268.3 mL
Therefore, approximately 268.3 mL of water must be added to the 35.0 mL of 23.0 M HCl to make the solution 3.00 M.
To find the volume of water that needs to be added, we can use the formula for dilution:
(C1)(V1) = (C2)(V2)
Where:
C1 = initial concentration of the HCl solution (23.0 M)
V1 = initial volume of the HCl solution (35.0 mL)
C2 = final concentration of the diluted solution (3.00 M)
V2 = final volume of the diluted solution
Rearranging the formula, we have:
V2 = (C1)(V1) / C2
Now we can substitute the values:
V2 = (23.0 M)(35.0 mL) / 3.00 M
Calculating this expression will give us the final volume of the diluted solution, which is the volume of water that needs to be added.