a 1000 kg car traveling at 30 m/s suddenly stops in 5 seconds. how much force was used to stop the car?

force*time=mass*changeinVelocity

so... F*5+-30*1000 which equals 6000??

no.

force= 30*1000/5, oh, yes, 6000N

To calculate the force used to stop the car, you need to use Newton's second law of motion, which states that the force applied to an object is equal to the product of its mass and acceleration. In this case, we want to find the force required to stop the car, so we need to determine the acceleration experienced by the car.

Acceleration is defined as the change in velocity divided by the time taken. The car starts at a velocity of 30 m/s and comes to a stop in 5 seconds, so the change in velocity can be calculated as follows:

Change in velocity = Final velocity - Initial velocity = 0 m/s - 30 m/s = -30 m/s

Since the car is slowing down, the change in velocity is negative.

Next, we can calculate the acceleration using the formula:

Acceleration = Change in velocity / Time taken

Acceleration = (-30 m/s) / (5 s) = -6 m/s^2

Notice that the acceleration is negative because it is in the opposite direction of the car's motion. This negative sign indicates deceleration or slowing down.

Now that we have the acceleration, we can calculate the force using Newton's second law:

Force = Mass × Acceleration

Force = 1000 kg × (-6 m/s^2)

Force = -6000 N

The force required to stop the car is -6000 Newtons (N). The negative sign indicates that the force is applied in the opposite direction of the car's motion, effectively slowing it down.