write the equation in slope intercept form 6x+3y=12 i got y=2x+4 but i don't think i am right please HELP!!!
y=-2x+4 when u bring over the 6x it turns negative.
okay that's what i wasn't sure of thanks
Your welcome
To write the equation 6x + 3y = 12 in slope-intercept form (y = mx + b), we need to isolate y on one side of the equation. Here are the steps to do that:
Step 1: Start with the given equation: 6x + 3y = 12.
Step 2: Subtract 6x from both sides to move the term containing x to the right side: 3y = -6x + 12.
Step 3: Divide both sides of the equation by 3 to isolate y: y = (-6/3)x + 12/3.
Step 4: Simplify the equation: y = -2x + 4.
So, after simplifying, the equation 6x + 3y = 12 can be written in slope-intercept form as y = -2x + 4.
Your initial answer, y = 2x + 4, is incorrect because the coefficient of x should be -2, not 2.