If you submerge an 5-kg log in water and it displaces 6 kg of water, what will the net force on the log be the moment you let go of the log?
aef
To determine the net force on the log the moment you let go of it, we need to consider the concept of buoyancy and the relationship between the weight of the log and the weight of the water it displaces.
The net force on the log can be calculated using Archimedes' principle, which states that the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.
The weight of the water displaced by the log is equal to the weight of the log itself. Therefore, the net force on the log will be zero as long as the log is in equilibrium and not accelerating in any direction.
Since the weight of the log is 5 kg and it displaces 6 kg of water, the net force on the log will be zero when you let go of it.
To summarize:
- The net force on the log will be zero when you let go of it because it displaces an amount of water greater than its own weight, resulting in buoyancy that counteracts its weight.
- This is based on Archimedes' principle, which states that the buoyant force acting on a submerged object is equal to the weight of the fluid displaced by the object.