How would you go about solving this? Im totally confused. Thanks!

Find the value of k such that the graph of f contains the given point. Write k as a simplified fraction if it is not a whole number.

f(x) = kx^3 - 3x^2 + kx + 3; (-1, 8)

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  1. Y = K(-1)^3-3(-1)^2+K(-1)+3 = 8,
    -K-3-K+3 = 8,
    -2K = 8,
    K = -4.

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