write the ionic equation and the net ionic equations.
1.AgNO3 and K2S
2.ZnCl2 and Na2SO4
3.CuCl2 and Li3PO4
2Ag(aq)^+ + S^-2(aq) ==> Ag2S(s)
#2. No reaction; therefore, simply show ZnCl2 and Na2SO4 as ions.
3Cu^+2(aq) + 2PO4^-3(aq) ==> Cu3(PO4)2(s)
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To write the ionic equation and net ionic equation for each given combination of compounds, you need to first identify the ions present in the reactants and then determine the products formed based on the combination of these ions. Here's how you can find the equations for each case:
1. AgNO3 and K2S:
a) AgNO3:
- Ag+ (silver ion)
- NO3- (nitrate ion)
b) K2S:
- K+ (potassium ion)
- S2- (sulfide ion)
Combining these ions, the products formed are Ag+ and S2- which form Ag2S:
Ag+ + S2- -> Ag2S (ionic equation)
In the net ionic equation, you eliminate the spectator ions that do not participate in the reaction. In this case, the spectator ions are K+ and NO3-. Hence, the net ionic equation is:
Ag+ + S2- -> Ag2S
2. ZnCl2 and Na2SO4:
a) ZnCl2:
- Zn2+ (zinc ion)
- Cl- (chloride ion)
b) Na2SO4:
- Na+ (sodium ion)
- SO4^2- (sulfate ion)
The products formed when these ions combine are Zn2+ and SO4^2- which form ZnSO4:
Zn2+ + SO4^2- -> ZnSO4 (ionic equation)
In the net ionic equation, you eliminate the spectator ions which are Na+ and Cl-. Hence, the net ionic equation is:
Zn2+ + SO4^2- -> ZnSO4
3. CuCl2 and Li3PO4:
a) CuCl2:
- Cu^2+ (copper ion)
- Cl- (chloride ion)
b) Li3PO4:
- Li+ (lithium ion)
- PO4^3- (phosphate ion)
The products formed when these ions combine are Cu^2+ and PO4^3- which form Cu3(PO4)2:
Cu^2+ + PO4^3- -> Cu3(PO4)2 (ionic equation)
In the net ionic equation, you eliminate the spectator ions which are Cl- and Li+. Hence, the net ionic equation is:
Cu^2+ + PO4^3- -> Cu3(PO4)2
These are the ionic equations and net ionic equations for the given combinations of compounds.