A 1440-kg crate of cabbages is laid on a level, frictionless track at the end of a heavy spring. The spring is compressed a distance of 0.100 m by a force of 83500 N. When the spring is released, it propels the crate. the spring constant of the spring equals 835000 N/m.
What is the total amount of work done by the spring on the crate during the launch in J?
spring constant=835000/.1 in N/m
KE at launch= PE in spring
work done by spring= 1/2 k (.1)^2
To find the total amount of work done by the spring on the crate during the launch, we can use the equation for the work done by a spring:
Work = (1/2) * k * x^2
Where:
k is the spring constant (835000 N/m)
x is the distance the spring is compressed (0.100m)
Now we can plug in the values into the equation:
Work = (1/2) * 835000 N/m * (0.100m)^2
Simplifying the equation further:
Work = (1/2) * 835000 N/m * 0.010m^2
Work = 417500 N/m * 0.010m^2
Work = 4175 J
Therefore, the total amount of work done by the spring on the crate during the launch is 4175 Joules.