# Calculus

I need help with integrals and I need help with the problem.
Integral of 4/sqrt(x)dx

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1. Try differentiate
sqrt(x)
and see if what you get inspires you.

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2. Integral of 4/sqrt(x)dx=

(x)^(-1/2)dx=(x)^(-1/2)dx

Integral of 4/sqrt(x)dx=4*Integral of
(x)^(-1/2)dx

Integral of x^n dx= x^(n+1) / (n+1)

Integral of (x)^(-1/2)dx=x^(-1/2+1) / (-1/2+1)= x^(1/2) / (1/2)= 2*sqrt(x)

Integral of 4/sqrt(x)dx=4*2*sqrt(x)+C= 8*sqroot(x)+C

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3. i know that the derivative of that is 1/2x^(-1/2) i still don't know what to do

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4. oh wow thank you so much!! that makes sense!!

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