Calculate how many grams of Cu are needed to produce 15L of NO(g). Please help

15 L NO from what?

To calculate the number of grams of Cu needed to produce 15L of NO(g), you need to know the balanced chemical equation and the molar ratio between Cu and NO. The molar ratio can be found by comparing the coefficients of Cu and NO in the balanced equation.

Let's assume the balanced equation is:

2Cu + N2O2 -> 2Cu2O + NO

From the balanced equation, we can see that 2 moles of Cu react to produce 1 mole of NO. This means that the molar ratio between Cu and NO is 2:1.

To calculate the number of moles of NO produced from 15L, you need to know the volume of gas at standard temperature and pressure (STP) conditions, which is 1 mole.

Using the ideal gas law equation (PV = nRT), where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature, you can rearrange the equation to solve for n:

n = PV / RT

Since the volume is given in liters and the pressure and temperature are assumed to be at STP (1 atm, 273 K), you can substitute the values into the equation:

n(NO) = (1 atm * 15 L) / (0.0821 L atm/mol K * 273 K)

n(NO) ≈ 0.6762 mol

Now, using the molar ratio between Cu and NO, you can calculate the number of moles of Cu needed:

n(Cu) = 2 * n(NO)
n(Cu) = 2 * 0.6762 mol
n(Cu) ≈ 1.3524 mol

Finally, to calculate the grams of Cu needed, you need to use the molar mass of Cu, which is approximately 63.55 g/mol:

mass(Cu) = n(Cu) * molar mass(Cu)
mass(Cu) = 1.3524 mol * 63.55 g/mol
mass(Cu) ≈ 85.97 g

Therefore, approximately 85.97 grams of Cu are needed to produce 15 liters of NO(g) based on the given information and assumptions.