15.45 grams of solid potassium chlorate decomposes when heated to form potassium chloride and oxygen gas. assuming 100% yeild how many grams of solid potassium will be produced?

Here is an example.

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To determine the grams of solid potassium produced, we need to find the molar ratio between solid potassium chlorate and potassium chloride.

First, let's write the balanced chemical equation for this reaction:

2 KClO3(s) -> 2 KCl(s) + 3 O2(g)

According to the equation, 2 moles of potassium chlorate (KClO3) produce 2 moles of potassium chloride (KCl). Since the equation is balanced in terms of moles, we can use this ratio to calculate the moles of solid potassium chloride formed.

Now, we need to find the moles of solid potassium chlorate. To do this, we divide the given mass of potassium chlorate (15.45 grams) by its molar mass.

The molar mass of potassium chlorate (KClO3) can be found by adding the atomic masses of its constituent elements:

Molar mass of K = 39.1 g/mol
Molar mass of Cl = 35.45 g/mol
Molar mass of O = 16.00 g/mol

Now add them:
Molar mass of KClO3 = 39.1 + (35.45 + (3 * 16.00)) = 122.55 g/mol

Next, calculate the number of moles of potassium chlorate:

moles = mass / molar mass
moles = 15.45 g / 122.55 g/mol

Now that we have the moles of potassium chlorate, we can use the ratio from the balanced equation to determine the moles of potassium chloride produced:

moles of KCl = moles of KClO3 * (2 moles of KCl / 2 moles of KClO3)

Finally, we can find the mass of solid potassium chloride using its molar mass:

mass = moles * molar mass
mass = moles of KCl * molar mass of KCl

Now, let's substitute the values and calculate the final result:

moles of KCl = (15.45 g / 122.55 g/mol) * (2 mol KCl / 2 mol KClO3)
moles of KCl = 15.45 g / 122.55 g/mol

mass = (15.45 g / 122.55 g/mol) * (39.1 g/mol + 35.45 g/mol)
mass = 15.45 g / 122.55 g/mol * 74.55 g/mol

mass = 15.45 g / 122.55 g/mol * (74.55 g/mol)
mass = 15.45 g / 122.55 g/mol * 74.55 g/mol

After performing the calculations, we find that the mass of solid potassium produced would be approximately 9.36 grams (rounded to two decimal places) assuming 100% yield.