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A gardener wants to fence the largest possible rectangular area using 200 yards of fencing. Find the best length and width of the garden.

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math student 7

  1. please help me!

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    math student 7

  2. The largest area is a square.

    P = 4S
    200/4 = S

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    Ms. Sue

  4. even if it said rectangular?

    so its's 50 yd by 50 yd?

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    math student 7

  5. I also need help on this question:
    Sandra walked to the top of a hill at a speed of 2km/h, turned around and walked down the hill at a rate of 4km/h. The whole trip took 6 hoours. How many kilometers is it to the top of the hill?

    I thought it might be 6km but my math teacher checked it and said it wasn't.

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    math student 7

  6. hello?Ms. Sue????

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    math student 7

  8. A square is a rectangle. Yes. The largest area would be a square measuring 50 yards on each side.

    Her average speed is 3 km/hour.

    (3 * 6)/2 = ?

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    Ms. Sue

  9. W=Width

    L=Length

    P=Perimeter

    A=Area

    P=2(W+L)

    200=2(W+L) Divide with 2

    100=W+L

    100-L=W

    W=100-L

    A=W*L=(100-L)*L

    A=100L-L^2

    dA/dL=100-2L

    Function has minimum or maximum when first derivate=0

    100-2L=0

    100=2L Divide with 2

    50=L

    L=50 yd

    If second derivate<0 then function has a maximum.

    If second derivate>0 then function has a minimum.

    Second derivate=-2<0
    function has a maximum for L=50 yd

    W=100-L

    W=100-50=50 yd

    A(max)=50*50=2500 yd^2

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    Bosnian

  10. what do you do with (*)

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    math student 7

  12. * is sign for multiply

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    Bosnian

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