A gas has a volume of V1 = 550 mL. If the
temperature is held constant, what volume
would the gas occupy if P2 = 22 P1?
P1V1= P2V2
Let P1= P1
(550mL)(P1)= (V2)(22P1)
P1 Cancels Out.
V2 = 550/22 mL
To determine the volume of the gas when the pressure changes, we can use Boyle's Law. Boyle's Law states that the product of pressure and volume is constant as long as the temperature remains constant.
The equation can be stated as follows:
P1 * V1 = P2 * V2
Where:
P1 and P2 are the initial and final pressure values
V1 and V2 are the initial and final volume values
In this case, we are given that the initial volume is V1 = 550 mL. The relationship between P2 and P1 is given as P2 = 22 * P1.
To find the final volume V2, we can rearrange the equation and solve for V2:
P1 * V1 = P2 * V2
Dividing both sides of the equation by P2:
V2 = (P1 * V1) / P2
Plugging in the given values:
V2 = (P1 * 550 mL) / (22 * P1)
The P1 cancels out, simplifying the equation:
V2 = (550 mL) / 22
Calculating:
V2 = 25 mL
Therefore, if the temperature is held constant and the pressure changes to 22 times the initial pressure, the gas would occupy a volume of 25 mL.