the product of 4 prime numbers is 2145. the product of two of them is 65. the sum of the other two must be:
A 16 B 8 C 24 D 14
give me direct answe A B C or D
a*b*c*d=2145
a*b=65
a*b*c*d=2145
65*c*d=2145
c*d=2145/65=33
c*d=33
Only two prime numbers with that product is
3 and 11
3*11=33
3+11=14
Answer D
To find the sum of the other two prime numbers, we can first determine the primes that multiply together to get 65.
The prime factors of 65 are 5 and 13.
Now, we need to find the remaining two prime numbers that multiply together to get 2145, excluding the primes we have already found.
2145 ÷ (5 × 13) = 33
So, the remaining two prime numbers are 33 and another prime number.
To find this prime number, we divide 33 by the only other prime numbers less than or equal to the square root of 33 (which is approximately 5.74). The prime numbers we check are 2, 3, 5.
33 ÷ 3 = 11
Therefore, the remaining two prime numbers are 11 and 33.
To find their sum: 11 + 33 = 44
So, the sum of the other two prime numbers is 44.
Therefore, the answer is C: 24.