b) A ball of mass 3.5 kg starts from rest and slides down a rough inclined plane 60 cm long
in 0.6 s.
i) Calculate the net force acting on the object along the inclined plane
http://m.dictionary.com/d/?q=physics&o=0&l=dir
Note that "ph" and "f" make the same phonetic sounds.
Note other letters as well.
To calculate the net force acting on the object along the inclined plane, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.
First, we need to find the acceleration of the ball along the inclined plane. We can use the kinematic equation:
\[x = ut + \frac{1}{2}at^2\]
where:
- x is the displacement along the inclined plane (60 cm or 0.6 m),
- u is the initial velocity (0 m/s since the ball starts from rest),
- t is the time (0.6 s), and
- a is the acceleration (which we want to find).
Rearranging the equation, we have:
\[a = \frac{2(x - ut)}{t^2}\]
Plugging in the values, we get:
\[a = \frac{2(0.6 - 0)}{(0.6)^2} = \frac{2(0.6)}{0.36} \approx 3.33 \, \text{m/s}^2\]
Now that we have the acceleration, we can calculate the net force by multiplying the mass of the ball (3.5 kg) by the acceleration:
\[F_{\text{net}} = ma = 3.5 \, \text{kg} \times 3.33 \, \text{m/s}^2 \approx 11.66 \, \text{N}\]
Therefore, the net force acting on the object along the inclined plane is approximately 11.66 N.