HOW YOU PREPARE 30.0ML OF 0.800M HNO3 FROM A STOCK SOLUTION OF 4.OOM HNO3? WHAT SOLUTION IN ML OF THE 4.OOM HNO3 SOLUTION WILL YOU NEED?

Please don't use caps. It makes the question difficult to read.

mL x M = mL x M
mL x 4.00 = 30.0 x 0.800
mL HNO3 stock = (30.0 x 0.800/4.00) = 6.00 mL.
So, measure 6.0 mL of the stock 4.00 M HNO3 and add enough water to make 30.0 mL final volume. That will be very close to 24 mL (30.0-6.0 = 24.0 mL) of water.

Oh boy, it's math time! To prepare 30.0 mL of a 0.800 M HNO3 solution from a stock solution of 4.00 M HNO3, we can use the formula C1V1 = C2V2. C1 represents the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume. Plugging in the given values:

(4.00 M)(V1) = (0.800 M)(30.0 mL)

Solving for V1:

V1 = (0.800 M)(30.0 mL) / (4.00 M)

V1 ≈ 6.00 mL

So you'll need approximately 6.00 mL of the 4.00 M HNO3 solution! Just remember to be precise with your measurements and, as always, don't clown around.

To prepare 30.0 mL of a 0.800 M HNO3 solution from a stock solution of 4.00 M HNO3, you can use the following steps:

Step 1: Determine the moles of HNO3 required in the final solution.
Given: Volume of final solution (Vf) = 30.0 mL = 0.0300 L
Concentration of final solution (Cf) = 0.800 M
Using the formula: moles = concentration × volume
Moles of HNO3 required (n) = Cf × Vf

Step 2: Calculate the volume of the stock solution needed.
Given: Concentration of stock solution (Cs) = 4.00 M
Volume of stock solution (Vs) = ?
Using the formula: moles = concentration × volume
Moles of HNO3 in the stock solution (n) = Cs × Vs

Since the moles of HNO3 required in the final solution (Step 1) is the same as the moles of HNO3 in the stock solution (Step 2), we can equate them:
Cs × Vs = Cf × Vf

Step 3: Solve for the volume of the stock solution needed (Vs).
Rearranging the equation from Step 2:
Vs = (Cf × Vf) / Cs

Now, let's substitute the given values into the equation to calculate the volume of the stock solution needed:

Vs = (0.800 M × 0.0300 L) / 4.00 M
Vs = 0.0060 L or 6.0 mL

Therefore, to prepare a 30.0 mL of 0.800 M HNO3 solution, you will need 6.0 mL of the 4.00 M HNO3 stock solution.

To prepare 30.0 mL of a 0.800 M HNO3 solution from a stock solution of 4.00 M HNO3, you can use the formula:

C1V1 = C2V2

Where:
C1 = concentration of initial solution (4.00 M)
V1 = volume of initial solution needed (unknown)
C2 = concentration of final solution (0.800 M)
V2 = volume of final solution (30.0 mL)

Rearranging the formula, we get:

V1 = (C2 * V2) / C1

Substituting the given values, we have:

V1 = (0.800 M * 30.0 mL) / 4.00 M

V1 = 4.8 mL

Therefore, to prepare 30.0 mL of a 0.800 M HNO3 solution from a stock solution of 4.00 M HNO3, you will need 4.8 mL of the 4.00 M HNO3 solution.