What is the pH of a solution that is 0.40 M in sulfurous acid (H2SO3) and )0.22 M in sodium sulfite (NaHSO3-)? Ka (H2SO3) = 1.3x10-2

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  1. Use the Henderson-Hasselbalch equation.
    pH = pKa + log (base)/(acid).

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  2. Thanks :) I did that and got 1.63 as my pH, which is the correct answer.

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