calculate the molar concentration of H3PO4 in the cola sample.
Volume of decarbonated cola used 25.00mL, Molarity of NaOH used for titration 0.0100M, and Volume NaOH used at first equivalence point is 14.54mL.
See your other post above. Same process; different numbers.
To calculate the molar concentration of H3PO4 in the cola sample, we can use the concept of stoichiometry and the data provided.
The balanced chemical equation for the reaction between H3PO4 and NaOH is:
H3PO4 + 3NaOH -> Na3PO4 + 3H2O
From the balanced equation, we can see that 1 mole of H3PO4 reacts with 3 moles of NaOH. Therefore, the moles of H3PO4 can be calculated by the following equation:
moles of H3PO4 = moles of NaOH / 3
Now, let's calculate the moles of NaOH used:
moles of NaOH = Molarity of NaOH x Volume of NaOH used (L)
= 0.0100 M x 0.01454 L
= 0.0001454 moles
Using the stoichiometry relationship mentioned earlier, we can determine the moles of H3PO4:
moles of H3PO4 = 0.0001454 moles / 3
= 4.847 x 10^-5 moles
Now, let's calculate the molar concentration of H3PO4 in the cola sample by dividing the moles of H3PO4 by the volume of cola used (converted to liters):
molar concentration of H3PO4 = moles of H3PO4 / volume of cola used (L)
= 4.847 x 10^-5 moles / (25.00 mL / 1000)
= 1.939 x 10^-3 M
Therefore, the molar concentration of H3PO4 in the cola sample is 1.939 x 10^-3 M.