Algebra

put the following into mx+b form.
x+1/6y=1/2

I got either y=-x+1/12
y=-x+3

I don't know which one.

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  1. x + (1/6)y = 1/2
    to transform this into y = mx + b, first we isolate the y term into the left side of equation,, thus the x on the left side must be transposed to the right side. to do this we change the sign of x to its opposite (positive becomes negative):
    x + (1/6)y = 1/2
    (1/6)y = -x + 1/2
    now since the numerical coefficient of y must be 1, we multiply both sides of equation by 6, so that (1/6)*6 = 1 :
    (1/6)*6 y = ( -x + 1/2 )*6
    y = -6x + 3

    hope this helps~ :)

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