how much heat is absorbed when 500.g of copper goes from 25.0 celcius to 35.0 celcius?

Note the correct spelling of celsius.

q = mass Cu x specific heat Cu x (Tfinal-Tinitial)

To calculate the amount of heat absorbed by an object, you need to use the formula:

Q = m * C * ΔT

Where:
Q = heat transferred
m = mass of the substance (in grams)
C = specific heat capacity of the substance (in J/g°C)
ΔT = change in temperature (in °C)

In this case, you have:
m = 500 g (mass of copper)
C = specific heat capacity of copper (0.39 J/g°C)
ΔT = 35.0°C - 25.0°C = 10.0°C (change in temperature)

Now, let's plug the values into the formula and calculate:

Q = 500 g * 0.39 J/g°C * 10.0°C

Q = 1,950 J

Therefore, when 500 g of copper goes from 25.0°C to 35.0°C, it absorbs 1,950 J (joules) of heat.

133j