find the area of a pentagon with the co ordinates of A(0,4) B(3,2) C(3,-1) D(-3,-1) E(-3,2)
See
http://www.jiskha.com/display.cgi?id=1302081233
What is 1 possible shape of figure for 36 cm(above cm is 2 didn't know how to put it sorry)
97 sq.unit
To find the area of a pentagon with given coordinates, you can use the method of shoelace formula (also known as Gauss's area formula).
The shoelace formula calculates the area of a polygon by using the coordinates of its vertices. The formula states that the area of a polygon with vertices (x1, y1), (x2, y2), (x3, y3), ..., (xn, yn) is equal to:
Area = |(x1 * y2 + x2 * y3 + x3 * y4 + ... + xn * y1) - (y1 * x2 + y2 * x3 + y3 * x4 + ... + yn * x1)| / 2
Let's apply this formula to your coordinates A(0,4), B(3,2), C(3,-1), D(-3,-1), E(-3,2) to find the area of the pentagon.
1. Write down the coordinates in a clockwise or counterclockwise order:
A (0, 4)
B (3, 2)
C (3, -1)
D (-3, -1)
E (-3, 2)
2. Multiply the x-coordinate of each point by the y-coordinate of the next point, and sum these values:
(0 * 2) + (3 * -1) + (3 * -1) + (-3 * 2) + (-3 * 4) = 0 - 3 - 3 - 6 - 12 = -24
3. Multiply the y-coordinate of each point by the x-coordinate of the next point, and sum these values:
(4 * 3) + (2 * 3) + (-1 * -3) + (-1 * -3) + (2 * 0) = 12 + 6 + 3 + 3 + 0 = 24
4. Take the absolute value of the difference between the two sums:
Abs(-24 - 24) = Abs(-48) = 48
5. Divide the result by 2 to get the area of the pentagon:
48 / 2 = 24
Therefore, the area of the pentagon with coordinates A(0,4), B(3,2), C(3,-1), D(-3,-1), E(-3,2) is 24 square units.