DYNAMICS:
A 54kg fireman slides down a pole of a distance of 3m. if the man hits the groung at 4.4m/s than what will the force of friction acting on the man due to the pole?
If he fell without holding a pole, he would hit the ground at speed
V = sqrt(2gH) = 7.67 m/s
If his actual speed 4.4 m/s, convert the loss of kinetic energy.
KE loss = (M/2)[(7.67)^2 - (4.4)^2]
= 1066 Joules
Set that equal to friction force x 3 m (the work done against friction) and solve for the friction force.